If one of the lines given by k x^2 + x y - y^ | vedclass

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(B) The equation of the pair of lines is $k x^2 + x y - y^2 = 0$. Since the lines bisect the angle between the coordinate axes,their slopes must be $m

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$0$ and $2$

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(B) The equation of the pair of lines is $k x^2 + x y - y^2 = 0$. Since the lines bisect the angle between the coordinate axes,their slopes must be $m = \pm 1$. Substituting $y = mx$ into the equation,we get $k x^2 + x(mx) - (mx)^2 = 0$. Dividing by $x^2$ (assuming $x 
eq 0$),we get $k + m - m^2 = 0$. For $m = 1$,$k + 1 - 1^2 = 0 \Rightarrow k = 0$. For $m = -1$,$k - 1 - (-1)^2 = 0$ $\Rightarrow k - 1 - 1 = 0$ $\Rightarrow k = 2$. Thus,the values of $k$ are $0$ and $2$.

If one of the lines given by $k x^2 + x y - y^2 = 0$ bisects the angle between the coordinate axes,then the values of $k$ are

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