If in nature there may not be an element for | vedclass

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Question

(a) For $n=1,$ maximum number of states $ = 2{n^2} = 2$ and for $n = 2, 3, 4,$ maximum number of states would be $8, 18, 32$ respectively, Hence numbe

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(a) For $n=1,$ maximum number of states $ = 2{n^2} = 2$ and for $n = 2, 3, 4,$ maximum number of states would be $8, 18, 32$ respectively, Hence number of possible elements
$= 2 + 8 + 18 + 32 = 60.$

If in nature there may not be an element for which the principal quantum number $n > 4,$ then the total possible number of elements will be

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