If in nature there may not be an element for | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The maximum number of electrons (and thus elements) that can be accommodated in a shell with principal quantum number $n$ is given by the formula

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(A) The maximum number of electrons (and thus elements) that can be accommodated in a shell with principal quantum number $n$ is given by the formula $2n^2$.For $n = 1$,the number of elements is $2(1)^2 = 2$.For $n = 2$,the number of elements is $2(2)^2 = 8$.For $n = 3$,the number of elements is $2(3)^2 = 18$.For $n = 4$,the number of elements is $2(4)^2 = 32$.Since the principal quantum number $n$ cannot exceed $4$,the total number of possible elements is the sum of elements in shells $n=1, 2, 3,$ and $4$.Total elements $= 2 + 8 + 18 + 32 = 60$.

List-$I$	List-$II$
$1$. Nitrogen molecules	$(A)$ Continuous spectrum
$2$. Incandescent solids	$(B)$ Absorption spectrum
$3$. Fraunhofer lines	$(C)$ Band spectrum
$4$. Electric arc between iron rods	$(D)$ Emission spectrum

$1$. Burning candle	$i$. Line spectrum
$2$. Sodium vapour	$ii$. Continuous spectrum
$3$. Bunsen flame	$iii$. Band spectrum
$4$. Dark lines in solar spectrum	$iv$. Absorption spectrum

If in nature there may not be an element for which the principal quantum number $n > 4,$ then the total possible number of elements will be

Similar Questions

Match the appropriate pairs from List-$I$ and List-$II$:
List-$I$ List-$II$
$1$. Nitrogen molecules $(A)$ Continuous spectrum
$2$. Incandescent solids $(B)$ Absorption spectrum
$3$. Fraunhofer lines $(C)$ Band spectrum
$4$. Electric arc between iron rods $(D)$ Emission spectrum

Match the following:
$1$. Burning candle $i$. Line spectrum
$2$. Sodium vapour $ii$. Continuous spectrum
$3$. Bunsen flame $iii$. Band spectrum
$4$. Dark lines in solar spectrum $iv$. Absorption spectrum

The solar spectrum is an example of

An electron passing through a potential difference of $4.9 \ V$ collides with a mercury atom and transfers it to the first excited state. What is the wavelength of a photon corresponding to the transition of the mercury atom to its normal state in $\mathring{A}$?

In a $He-Ne$ laser,the metastable state exists in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module