An electron passing through a potential diffe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The energy transferred to the mercury atom is equal to the kinetic energy gained by the electron,which is $E = eV = 4.9 \ eV$.This energy correspo

Vedclass · Accepted Answer

$2525$

Vedclass · Answer

(C) The energy transferred to the mercury atom is equal to the kinetic energy gained by the electron,which is $E = eV = 4.9 \ eV$.This energy corresponds to the transition from the first excited state to the ground state.The relationship between energy and wavelength is given by $E = \frac{hc}{\lambda}$.Rearranging for wavelength: $\lambda = \frac{hc}{E}$.Substituting the values: $h = 6.63 	imes 10^{-34} \ J \cdot s$,$c = 3 	imes 10^8 \ m/s$,and $E = 4.9 	imes 1.6 	imes 10^{-19} \ J$.$\lambda = \frac{6.63 	imes 10^{-34} 	imes 3 	imes 10^8}{4.9 	imes 1.6 	imes 10^{-19}} \ m$.$\lambda \approx 2.536 	imes 10^{-7} \ m = 2536 \ \mathring{A}$.Given the options provided,the closest value is $2525 \ \mathring{A}$.

An electron passing through a potential difference of $4.9 \ V$ collides with a mercury atom and transfers it to the first excited state. What is the wavelength of a photon corresponding to the transition of the mercury atom to its normal state in $\mathring{A}$?

Similar Questions

The collision of an electron with kinetic energy $5.5 eV$ and a hydrogen atom in its ground state can be described as

Which of the following elements was discovered by the study of Fraunhofer lines?

The number of completely filled shells for the element ${ }_{16} S ^{32}$ is

When light emitted by a white hot solid is passed through a sodium flame,the spectrum of the emergent light will show

The spectrum obtained from a sodium vapour lamp is an example of

Vedclass Test Series

Exam Paper Generator

Online Exam Module