If in a long division sum,the dividend is $380606$ and the successive remainders from the first to the last are $434, 125,$ and $413,$ then the divisor is:

  • A
    $451$
  • B
    $843$
  • C
    $4215$
  • D
    $3372$

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Similar Questions

The product of three consecutive even numbers is $4032$. The product of the first and the third number is $252$. What is five times the second number?

Difficult
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$\left[ {8\left\{ {\left( {\frac{{21 \times \sqrt {\frac{9}{{441}}} }}{5} \text{ of } 60\% - \frac{1}{5}} \right) \times 625 + 7} \right\} \div 4} \right] = ?$

Difficult
View Solution

$441.01 - 232.99 + 1649.99 = ? + 1225.92$

Two numbers are such that the ratio between them is $3:5;$ but if each is increased by $10,$ the ratio between them becomes $5:7.$ The numbers are

What is the value of $\left(\frac{3}{5} + \frac{7}{9}\right)$?

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