$\left[ {8\left\{ {\left( {\frac{{21 \times \sqrt {\frac{9}{{441}}} }}{5} \text{ of } 60\% - \frac{1}{5}} \right) \times 625 + 7} \right\} \div 4} \right] = ?$

The sum of nine consecutive odd numbers of Set $A$ is $621$. What is the sum of a different set of six consecutive even numbers whose lowest number is $15$ more than the lowest number of Set $A$?

$18.5 \%$ of $220 + 12.4 \%$ of $680 = ?$

$A$ number when divided by $361$ gives a remainder $47$. If the same number is divided by $19$,the remainder obtained is

For what value of $K$,the number $7236K2$ is divisible by $8$?

$(0.25)^{6} \div (0.125)^{2} \times (0.5)^{4} = (0.5)^{?+3}$