(C) The force on the bullet is given by $F = 600 - 2 \times 10^5 t$.When the bullet leaves the barrel,the force becomes zero,so $F = 0$.$600 - 2 \time

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(C) The force on the bullet is given by $F = 600 - 2 \times 10^5 t$.When the bullet leaves the barrel,the force becomes zero,so $F = 0$.$600 - 2 \times 10^5 t = 0$$2 \times 10^5 t = 600$$t = \frac{600}{2 \times 10^5} = 3 \times 10^{-3} \ s$.Impulse $I$ is defined as the integral of force with respect to time: $I = \int_{0}^{t} F \ dt$.$I = \int_{0}^{3 \times 10^{-3}} (600 - 2 \times 10^5 t) \ dt$$I = [600t - 10^5 t^2]_{0}^{3 \times 10^{-3}}$$I = 600(3 \times 10^{-3}) - 10^5(3 \times 10^{-3})^2$$I = 1.8 - 10^5(9 \times 10^{-6})$$I = 1.8 - 0.9 = 0.9 \ N-s$.

Class 11 Physics Newton's Laws of Motion and Friction Third Law of Motion and Momentum and Impulse

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$A$ bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 \times 10^5 t$,where $F$ is in newtons and $t$ is in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the impulse imparted to the bullet in $N-s$?

AIPMT 1998 All AIPMT

A
$9$
B
$0$
C
$0.9$
D
$1.8$

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Newton's Laws of Motion and Friction

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Third Law of Motion and Momentum and Impulse

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$A$ bullet is fired from a gun. The force on the bullet is given by $F = 600 - 2 \times 10^5 t$,where $F$ is in newtons and $t$ is in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the impulse imparted to the bullet in $N-s$?

Similar Questions

$A$ jet of water with cross-sectional area $A$ strikes a wall at an angle $\theta$ with the normal to the wall and rebounds elastically. If the density of water is $\rho$ and the velocity is $v$,what is the force exerted on the wall?

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