$A$ particle of mass $m$, initially at rest, is acted upon by a variable force $F$ for a brief interval of time $T$. It begins to move with a velocity $u$ after the force stops acting. The graph shows $F$ as a function of time, where the curve is a semicircle with peak force $F_0$ at time $T/2$.

  • A
    $u = \frac{\pi F_0^2}{2m}$
  • B
    $u = \frac{\pi T^2}{8m}$
  • C
    $u = \frac{\pi F_0 T}{4m}$
  • D
    $u = \frac{F_0 T}{2m}$

Explore More

Similar Questions

Swimming is possible on account of

Two particles of masses $m_1$ and $m_2$ in projectile motion have velocities $\vec{v}_1$ and $\vec{v}_2$ respectively at time $t = 0$. They collide at time $t_0$. Their velocities become $\vec{v}_1'$ and $\vec{v}_2'$ at time $2t_0$ while still moving in air. The value of $|(m_1\vec{v}_1' + m_2\vec{v}_2') - (m_1\vec{v}_1 + m_2\vec{v}_2)|$ is

$A$ particle of mass $m \, kg$ moving with a velocity $v \, m/s$ strikes a surface as shown in the figure and rebounds with the same speed. The magnitude of the change in momentum is:

The position-time graph of a body of mass $2\, kg$ is as given in the figure. What is the impulse on the body at $t = 0\, s$ and $t = 4\, s$ (in $, Ns$)?

The figure shows the position-time graph of a particle of mass $4 \,kg$. What is the
$(a)$ force on the particle for $t < 0$,$t > 4 \,s$,and $0 < t < 4 \,s$?
$(b)$ impulse at $t = 0$ and $t = 4 \,s$? (Consider one-dimensional motion only).

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo