If Hund's rule is violated,then select the CO | vedclass

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(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.If $Hund's$ rule is violated,the $8$ electrons in the

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$d^2sp^3$,diamagnetic

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(B) The atomic number of $Ni$ is $28$. The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.If $Hund's$ rule is violated,the $8$ electrons in the $3d$ orbitals would pair up in the lower energy orbitals first.Specifically,the $3d$ orbitals would be filled as: $(d_{xy})^2 (d_{yz})^2 (d_{zx})^2 (d_{x^2-y^2})^2 (d_{z^2})^0$.This leaves two inner $d$-orbitals ($d_{x^2-y^2}$ and $d_{z^2}$) vacant.These two vacant $d$-orbitals,along with one $4s$ and three $4p$ orbitals,undergo $d^2sp^3$ hybridization.Since all electrons are paired in this configuration,the complex becomes diamagnetic.Therefore,the correct statement is $d^2sp^3$ and diamagnetic.

If $Hund's$ rule is violated,then select the $CORRECT$ statement regarding $[Ni(NH_3)_6]^{2+}$:

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The structure of iron pentacarbonyl is:

$[Co(C_2O_4)_3]^{3-}$ is a :

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
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$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

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