Nickel combines with a uninegative monodentat | vedclass

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(A) The central metal ion is $Ni^{2+}$,which has an electronic configuration of $[Ar] 3d^8$.Since the complex $[NiX_4]^{2-}$ is paramagnetic and has a

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$sp^3$,two

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(A) The central metal ion is $Ni^{2+}$,which has an electronic configuration of $[Ar] 3d^8$.Since the complex $[NiX_4]^{2-}$ is paramagnetic and has a coordination number of $4$,it adopts a tetrahedral geometry.In a tetrahedral geometry,the hybridisation is $sp^3$.For $Ni^{2+}$ $(3d^8)$,the $3d$ orbitals have two unpaired electrons.Therefore,the hybridisation is $sp^3$ and the number of unpaired electrons is $2$.

Nickel combines with a uninegative monodentate ligand $(X^{-})$ to form a paramagnetic complex $[NiX_4]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively:

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