If an electron revolves around a nucleus in a circular orbit of radius $R$ with frequency $n$, then the magnetic field produced at the centre of the nucleus will be
If an electron revolves around a nucleus in a circular orbit of radius $R$ with frequency $n$, then the magnetic field produced at the centre of the nucleus will be
- A
$\frac{\mu_0 e n}{2 R}$
- B
$\frac{\mu_0 e n}{4 \pi R}$
- C
$\frac{4 \pi \mu_0 e n}{R}$
- D
$\frac{4 \pi \mu_0 e}{R n}$
Similar Questions
The radius of a circular current carrying coil is $R$. At what distance from the centre of the coil on its axis, the intensity of magnetic field will be $\frac{1}{2 \sqrt{2}}$ times that at the centre?
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Due to the presence of the current $I_1$ at the origin
- [AIEEE 2009]
A thin wire of length $l$ is carrying a constant current. The wire is bent to form a circular coil. If radius of the coil, thus formed, is equal to $R$ and number of turns in it is equal to $n$, then which of the following graphs represent $(s)$ variation of magnetic field induction $(b)$ at centre of the coil
A thin wire of length $l$ is carrying a constant current. The wire is bent to form a circular coil. If radius of the coil, thus formed, is equal to $R$ and number of turns in it is equal to $n$, then which of the following graphs represent $(s)$ variation of magnetic field induction $(b)$ at centre of the coil
Give $\mathrm{SI}$ unit of magnetic field from Biot-Savart law.
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