If a variable takes the discrete values alpha | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) First,arrange the given $8$ values in ascending order:
$\alpha - 4, \alpha - 3.5, \alpha - 3, \alpha - 2.5, \alpha - 2, \alpha - 0.5, \alpha + 0.

Vedclass · Accepted Answer

$\alpha - \frac{9}{4}$

Vedclass · Answer

(D) First,arrange the given $8$ values in ascending order:
$\alpha - 4, \alpha - 3.5, \alpha - 3, \alpha - 2.5, \alpha - 2, \alpha - 0.5, \alpha + 0.5, \alpha + 5$
Since the number of observations $n = 8$ (which is even),the median is the average of the $4^{th}$ and $5^{th}$ terms.
$4^{th} 	ext{ term} = \alpha - 2.5 = \alpha - \frac{5}{2}$
$5^{th} 	ext{ term} = \alpha - 2$
$	ext{Median} = \frac{(\alpha - \frac{5}{2}) + (\alpha - 2)}{2}$
$	ext{Median} = \frac{2\alpha - 4.5}{2} = \alpha - 2.25 = \alpha - \frac{9}{4}$

Class	$0-4$	$4-8$	$8-12$	$12-16$	$16-20$
Frequency	$3$	$9$	$10$	$8$	$6$

If a variable takes the discrete values $\alpha - 4, \alpha - \frac{7}{2}, \alpha - \frac{5}{2}, \alpha - 3, \alpha - 2, \alpha + \frac{1}{2}, \alpha - \frac{1}{2}, \alpha + 5$ (where $\alpha > 0$),then the median is:

Similar Questions

If $\bar{X}_1$ and $\bar{X}_2$ are the means of two series such that $\bar{X}_1 < \bar{X}_2$,and $\bar{X}$ is the combined mean of the two series,then which of the following is true?

If in an examination different weights are assigned to different subjects: Physics $(2)$,Chemistry $(1)$,English $(1)$,and Mathematics $(2)$. If a student scored $60$ in Physics,$70$ in Chemistry,$70$ in English,and $80$ in Mathematics,then his weighted $A.M.$ is:

Let $M$ denote the median of the following frequency distribution. Then $20M$ is equal to:

Class $0-4$ $4-8$ $8-12$ $12-16$ $16-20$

Frequency $3$ $9$ $10$ $8$ $6$

If the mean of the set of numbers ${x_1}, {x_2}, {x_3}, ..., {x_n}$ is $\bar x$,then the mean of the numbers ${x_i} + 2i$,$1 \le i \le n$ is

If the mean of the numbers $27 + x$,$31 + x$,$89 + x$,$107 + x$,and $156 + x$ is $82$,then the mean of $130 + x$,$126 + x$,$68 + x$,$50 + x$,and $1 + x$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module