If in an examination different weights are assigned to different subjects: Physics $(2)$,Chemistry $(1)$,English $(1)$,and Mathematics $(2)$. If a student scored $60$ in Physics,$70$ in Chemistry,$70$ in English,and $80$ in Mathematics,then his weighted $A.M.$ is:
- A$60$
- B$70$
- C$80$
- DNone of these
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Similar Questions
The following data gives the distribution of height of students:
Height (in $cm$) $160$ $150$ $152$ $161$ $156$ $154$ $155$ No of students $12$ $8$ $4$ $4$ $3$ $3$ $7$
The median of the distribution is:
| Height (in $cm$) | $160$ | $150$ | $152$ | $161$ | $156$ | $154$ | $155$ |
| No of students | $12$ | $8$ | $4$ | $4$ | $3$ | $3$ | $7$ |
The median of the distribution is:
Medium
View SolutionThe central value of the set of observations is called
Easy
View Solution$A$ school has four sections of chemistry in class $XII$ having $40, 35, 45$ and $42$ students. The mean marks obtained in chemistry test are $50, 60, 55$ and $45$ respectively for the four sections. The overall average of marks per student is:
Medium
View SolutionIf a variable takes the discrete values $\alpha - 4, \alpha - \frac{7}{2}, \alpha - \frac{5}{2}, \alpha - 3, \alpha - 2, \alpha + \frac{1}{2}, \alpha - \frac{1}{2}, \alpha + 5$ (where $\alpha > 0$),then the median is:
Medium
View SolutionIf the mean of a set of observations $x_1, x_2, \dots, x_{10}$ is $20$,then find the mean of $x_1 + 4, x_2 + 8, x_3 + 12, \dots, x_{10} + 40$.
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