If a straight line $L$ perpendicular to the line $3x - 4y = 6$ forms a triangle of area $6$ square units with the coordinate axes,then the minimum perpendicular distance from the point $(1, 1)$ to the line $L$ is

  • A
    $1$
  • B
    $\sqrt{2}$
  • C
    $2$
  • D
    $\sqrt{3}$

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