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Question

(A) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge enclosed by that surface divided by

Vedclass · Accepted Answer

$\frac{1}{\varepsilon_0} 	imes (	ext{charge enclosed by surface})$

Vedclass · Answer

(A) According to Gauss's Law,the total electric flux $\phi$ through any closed surface is equal to the net charge enclosed by that surface divided by the permittivity of free space $\varepsilon_0$.Mathematically,$\phi = \frac{Q_{	ext{enclosed}}}{\varepsilon_0}$.In the given figure,$Q_{	ext{enclosed}}$ is the portion of the charge on the spherical conductor that lies inside the dashed closed surface.Therefore,the total flux emitted from the surface is $\phi = \frac{1}{\varepsilon_0} 	imes Q_{	ext{enclosed}}$.

If a spherical conductor partially enters a closed surface as shown in the figure,then the total electric flux emitted from the closed surface will be:

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