If a particle is executing simple harmonic mo | vedclass

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(C) For a particle executing simple harmonic motion $(S.H.M.)$,the acceleration $a$ is given by the relation:$a = -\omega^2 x$where $\omega$ is the an

Vedclass · Accepted Answer

Is non-uniform

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(C) For a particle executing simple harmonic motion $(S.H.M.)$,the acceleration $a$ is given by the relation:$a = -\omega^2 x$where $\omega$ is the angular frequency and $x$ is the displacement from the mean position.Since the acceleration $a$ is directly proportional to the displacement $x$,it changes as the particle moves.Therefore,the acceleration is non-uniform because it depends on the position $x$ of the particle,not directly on time in a linear fashion (it varies sinusoidally with time).Thus,the correct option is $(c)$.

If a particle is executing simple harmonic motion,then the acceleration of the particle:

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