Give the formula of force acting on a particle executing simple harmonic motion.

$A$ particle is executing $S.H.M.$ Then the graph of acceleration as a function of displacement is

If a simple harmonic oscillator has a displacement of $0.02\, m$ and an acceleration equal to $2.0\, m\, s^{-2}$ at any time,the angular frequency of the oscillator is equal to .... $rad\, s^{-1}$.

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

$A$ body is executing $S.H.M.$ under the action of a force having a maximum magnitude of $50 \,N$. When its energy is half kinetic and half potential, the magnitude of the force acting on the particle is:

$A$ particle of mass $10 \, g$ performs simple harmonic motion with an amplitude of $0.5 \, m$ and an angular frequency of $10 \, rad/s$. What is the maximum force acting on it in $N$?