If a pair of equations 3x + ky - 9 = 0 and x | vedclass

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(B) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinite solutions,the condition is $\frac{a_1}{a_2} =

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$6$

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(B) For a pair of linear equations $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to have infinite solutions,the condition is $\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}$.Given equations are $3x + ky - 9 = 0$ and $x + 2y - 3 = 0$.Here,$a_1 = 3, b_1 = k, c_1 = -9$ and $a_2 = 1, b_2 = 2, c_2 = -3$.Applying the condition: $\frac{3}{1} = \frac{k}{2} = \frac{-9}{-3}$.This simplifies to $3 = \frac{k}{2} = 3$.From $\frac{k}{2} = 3$,we get $k = 3 	imes 2 = 6$.

If a pair of equations $3x + ky - 9 = 0$ and $x + 2y - 3 = 0$ has infinite solutions,then $k = \ldots$

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