If the lines given by 3x + 2ky = 2 and 2x + 5 | vedclass

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(A) The condition for two lines $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to be parallel is $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_

Vedclass · Accepted Answer

$\frac{15}{4}$

Vedclass · Answer

(A) The condition for two lines $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$ to be parallel is $\frac{a_1}{a_2} = \frac{b_1}{b_2} 
eq \frac{c_1}{c_2}$.Given the equations:$3x + 2ky - 2 = 0$$2x + 5y + 1 = 0$Here,$a_1 = 3, b_1 = 2k, c_1 = -2$ and $a_2 = 2, b_2 = 5, c_2 = 1$.For the lines to be parallel,we must have $\frac{a_1}{a_2} = \frac{b_1}{b_2}$.Substituting the values,we get $\frac{3}{2} = \frac{2k}{5}$.Cross-multiplying,we get $3 	imes 5 = 2 	imes 2k$,which implies $15 = 4k$.Therefore,$k = \frac{15}{4}$.

If the lines given by $3x + 2ky = 2$ and $2x + 5y + 1 = 0$ are parallel,then the value of $k$ is

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