Solve the following pairs of equations:frac{x | vedclass

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(D) Given,the pair of linear equations is:$\frac{x}{3} + \frac{y}{4} = 4$  $(i)$Multiplying both sides by the $LCM(3, 4) = 12$,we get:$4x + 3y = 48$

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$6, 8$

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(D) Given,the pair of linear equations is:$\frac{x}{3} + \frac{y}{4} = 4$  $(i)$Multiplying both sides by the $LCM(3, 4) = 12$,we get:$4x + 3y = 48$  $(iii)$And the second equation is:$\frac{5x}{6} - \frac{y}{8} = 4$  $(ii)$Multiplying both sides by the $LCM(6, 8) = 24$,we get:$20x - 3y = 96$  $(iv)$Now,adding equations $(iii)$ and $(iv)$,we get:$(4x + 3y) + (20x - 3y) = 48 + 96$$24x = 144$$x = \frac{144}{24} = 6$Now,substitute the value of $x = 6$ in equation $(iii)$:$4(6) + 3y = 48$$24 + 3y = 48$$3y = 48 - 24$$3y = 24$$y = 8$Thus,the solution is $x = 6$ and $y = 8$.

Solve the following pairs of equations:
$\frac{x}{3} + \frac{y}{4} = 4$
$\frac{5x}{6} - \frac{y}{8} = 4$

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Solve the following pairs of equations:$\frac{x}{3} + \frac{y}{4} = 4$$\frac{5x}{6} - \frac{y}{8} = 4$