If a haemophilic man marries a woman carrier | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Haemophilia is an $X$-linked recessive disorder.Let $X^h$ be the allele for haemophilia and $X$ be the normal allele.The genotype of a haemophilic

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(C) Haemophilia is an $X$-linked recessive disorder.Let $X^h$ be the allele for haemophilia and $X$ be the normal allele.The genotype of a haemophilic man is $X^hY$.The genotype of a carrier woman is $X^hX$.When they cross $(X^hY 	imes X^hX)$,the possible genotypes of the offspring are:$X^hX^h$ (Haemophilic daughter)$X^hX$ (Carrier daughter)$X^hY$ (Haemophilic son)$XY$ (Normal son)Out of the two possible female genotypes ($X^hX^h$ and $X^hX$),one is haemophilic $(X^hX^h)$.Therefore,the probability of having a haemophilic daughter is $1/2$ or $50\%$.

If a haemophilic man marries a woman carrier (heterozygous) for haemophilia,what would be the possibility that their daughter would be haemophilic (in $\%$)?

Similar Questions

Among symbols $A, B$ and $C$,what does $C$ indicate?

In the formation of the $\beta$-globin chain of hemoglobin,when valine replaces glutamic acid,the shape of the red blood cell becomes sickle-shaped,which leads to ....

Sickle cell anaemia is caused due to the substitution of

Which one of the following symbols represents mating between relatives in human pedigree analysis?

The pedigree chart given below shows a particular trait which is absent in parents but present in the next generation irrespective of sexes. Draw your conclusion on the basis of the pedigree.

Vedclass Test Series

Exam Paper Generator

Online Exam Module