If a body is in equilibrium under a set of non-collinear forces, then the minimum number of forces has to be
- [AIIMS 2000]
- A$4$
- B$3$
- C$2$
- D$5$
Similar Questions
A $1 \mathrm{~kg}$ mass is suspended from the ceiling by a rope of length $4 \mathrm{~m}$. A horizontal force ' $F$ ' is applied at the mid point of the rope so that the rope makes an angle of $45^{\circ}$ with respect to the vertical axis as shown in figure. The magnitude of $F$ is:
A $1 \mathrm{~kg}$ mass is suspended from the ceiling by a rope of length $4 \mathrm{~m}$. A horizontal force ' $F$ ' is applied at the mid point of the rope so that the rope makes an angle of $45^{\circ}$ with respect to the vertical axis as shown in figure. The magnitude of $F$ is:
- [JEE MAIN 2024]
A rope of mass $5 \,kg$ is hanging between two supports as shown alongside. The tension at the lowest point of the rope is close to ........... $N$ (take, $g=10 \,m / s ^{2}$ )
A rope of mass $5 \,kg$ is hanging between two supports as shown alongside. The tension at the lowest point of the rope is close to ........... $N$ (take, $g=10 \,m / s ^{2}$ )
- [KVPY 2017]
What are concurrent forces ? Explain equilibrium of particle under effect of concurrent forces.
What are concurrent forces ? Explain equilibrium of particle under effect of concurrent forces.
When a body is stationary
When a body is stationary
- [AIIMS 2005]
A mass of $5\, kg$ is suspended by a rope of length $2\,m$ from a ceiling. A force of $50\,N$ in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is ........ $^o$
A mass of $5\, kg$ is suspended by a rope of length $2\,m$ from a ceiling. A force of $50\,N$ in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is ........ $^o$