A uniform sphere of weight W and radius 3,m i | vedclass

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Question

$\mathrm{W}=\mathrm{T} \sin 	heta$

$\cos 	heta=3 / 5 \Rightarrow \quad 	heta=53^{\circ}$

$\mathrm{T}=\frac{\mathrm{W}}{\sin 53^{\circ}}=\frac

Vedclass · Accepted Answer

$5\,W/4$

Vedclass · Answer

$\mathrm{W}=\mathrm{T} \sin 	heta$

$\cos 	heta=3 / 5 \Rightarrow \quad 	heta=53^{\circ}$

$\mathrm{T}=\frac{\mathrm{W}}{\sin 53^{\circ}}=\frac{5}{4} \mathrm{W}$

A uniform sphere of weight $W$ and radius $3\,m$ is being held by a string of length $2\,m$ , attached to a frictionless wall as shown in the figure. The tension in the string will be

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