If a $12 \ pF$ capacitor is connected to a $50 \ V$ battery,then the electrostatic energy stored in the capacitor is . . . . . . .
- A$1.5 \times 10^{-12} \ J$
- B$1.5 \times 10^{-8} \ J$
- C$1.5 \times 10^{-6} \ J$
- D$3 \times 10^{-8} \ J$
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