What is the total energy of the given system | vedclass

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(C) The two capacitors are connected in parallel.The equivalent capacitance is given by $C_{eq} = C_1 + C_2 = 1 \ \mu F + 1 \ \mu F = 2 \ \mu F = 2

Vedclass · Accepted Answer

$0.04$

Vedclass · Answer

(C) The two capacitors are connected in parallel.The equivalent capacitance is given by $C_{eq} = C_1 + C_2 = 1 \ \mu F + 1 \ \mu F = 2 \ \mu F = 2 	imes 10^{-6} \ F$.The potential difference across the capacitors is $V = 200 \ V$.The total energy stored in the system is given by the formula $U = \frac{1}{2} C_{eq} V^2$.Substituting the values,we get $U = \frac{1}{2} 	imes (2 	imes 10^{-6} \ F) 	imes (200 \ V)^2$.$U = 10^{-6} 	imes 40000 = 0.04 \ J$.

What is the total energy of the given system in $joules$?

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