If overrightarrow A = 3hat i + hat j + 2hat k | vedclass

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Question

(b) $\overrightarrow A \, 	imes \,\overrightarrow B \, = \left|{\,\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\hat k}\{3\,\,}&{1\,

Vedclass · Accepted Answer

$8\sqrt 3 $

Vedclass · Answer

(b) $\overrightarrow A \, 	imes \,\overrightarrow B \, = \left|{\,\begin{array}{*{20}{c}}{\hat i\,\,}&{\hat j\,\,}&{\hat k}\{3\,\,}&{1\,\,}&2\{2\,\,\,}&{ - 2\,\,\,}&4\end{array}\,} ight|\,$

$ = (1 	imes 4 - 2 	imes - 2)\hat i + (2 	imes 2 - 4 	imes 3)\hat j + (3 	imes - 2 - 1 	imes 2)\hat k$

$ = 8\hat i - 8\hat j - 8\hat k$

$	herefore$ Magnitude of $\overrightarrow {m{A}} \, 	imes \overrightarrow {m{B}} \, = ,|\overrightarrow {m{A}} 	imes \overrightarrow {m{B}} |\, = \sqrt {{{(8)}^2} + {{( - 8)}^2} + {{( - 8)}^2}} \,$

$ = 8\sqrt 3 $

If $\overrightarrow A = 3\hat i + \hat j + 2\hat k$ and $\overrightarrow B = 2\hat i - 2\hat j + 4\hat k$ then value of $|\overrightarrow A \times \overrightarrow B |\,$ will be

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