If ${l_1}, {l_2}, {l_3}$ are the lengths of the emitter,base,and collector of a transistor,respectively,then:

In case of a bipolar transistor,$\beta = 45$. The potential drop across the collector resistance of $1 \ k\Omega$ is $5 \ V$. The base current is approximately: (in $\mu A$)

In a common emitter amplifier,the input resistance is $1000 \Omega$,the peak value of the input signal voltage is $5 mV$,and $\beta = 60$. The peak value of the output current is:

An $n-p-n$ transistor power amplifier in $C-E$ configuration gives

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$,then the power gain in the circuit is:

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).