(B) The voltage gain $(A_v)$ is given by:$A_v = \frac{\Delta V_o}{\Delta V_i} = \frac{\Delta I_c \times R_L}{\Delta V_i} = \frac{4 \times 10^{-3} \tim

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(B) The voltage gain $(A_v)$ is given by:$A_v = \frac{\Delta V_o}{\Delta V_i} = \frac{\Delta I_c \times R_L}{\Delta V_i} = \frac{4 \times 10^{-3} \times 10 \times 10^3}{40 \times 10^{-3}} = 1000$The current gain $(A_i)$ is given by:$A_i = \frac{\Delta I_c}{\Delta I_b} = \frac{4 \times 10^{-3}}{20 \times 10^{-6}} = 200$The power gain $(P)$ is the product of voltage gain and current gain:$P = A_v \times A_i = 1000 \times 200 = 2 \times 10^5$

Class 12 Physics Semiconductor Electronics Junction Transistor

Easy

Consider an amplifier circuit wherein a transistor is used in common emitter mode. The change in collector current and base current respectively are $4 mA$ and $20 \mu A$ when a signal of $40 mV$ is added to the base-emitter voltage. If the load resistance is $10 k\Omega$,then the power gain in the circuit is:

TS EAMCET 2018 All TS EAMCET

A
$1 \times 10^4$
B
$2 \times 10^5$
C
$8 \times 10^5$
D
$1 \times 10^6$

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Class 12

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Semiconductor Electronics

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Junction Transistor

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In a transistor $(\beta=50)$,the voltage across $5 \, k\Omega$ load resistance in the collector circuit is $5 \, V$. The base current is ......... $mA$.

Easy

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For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

MediumAIPMT 2002

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The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.

Easy

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When a signal is applied to the input of a transistor,it is found that the output signal is phase-shifted by $180^{\circ}$. The transistor configuration is:

EasyAP EAMCET 2024

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The load resistance and the base-emitter voltage of a transistor in $CE$ configuration are $5 \ k\Omega$ and $0.02 \ V$ respectively. If the collector current is $2 \ mA$,then its voltage gain is

EasyAP EAMCET 2023

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In a transistor $(\beta=50)$,the voltage across $5 \, k\Omega$ load resistance in the collector circuit is $5 \, V$. The base current is ......... $mA$.

For a common base configuration of a $PNP$ transistor,$\frac{I_C}{I_E} = 0.96$. Then,the maximum current gain in common emitter configuration will be:

The input resistance of a common-emitter amplifier is $2 \, k\Omega$ and a.c. current gain is $20$. If the load resistor used is $5 \, k\Omega$,calculate the transconductance of the transistor used in $\Omega^{-1}$.

When a signal is applied to the input of a transistor,it is found that the output signal is phase-shifted by $180^{\circ}$. The transistor configuration is:

The load resistance and the base-emitter voltage of a transistor in $CE$ configuration are $5 \ k\Omega$ and $0.02 \ V$ respectively. If the collector current is $2 \ mA$,then its voltage gain is

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