જો $f(3) = 6$ અને $f'(3) = 2$ હોય,તો $\mathop {\text{Limit}}\limits_{x \to 3} \frac{x f(3) - 3 f(x)}{x - 3}$ ની કિંમત શોધો:

  • A
    $6$
  • B
    $4$
  • C
    $0$
  • D
    આમાંથી કોઈ નહીં

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$\mathop {\lim }\limits_{\theta \to \pi /2} (\sec \theta - \tan \theta ) = $

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