If A = begin{bmatrix} 3 & 4 1 & -6 end{bmatr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given the equation $A + 2X = B$. Subtracting $A$ from both sides,we get $2X = B - A$. First,calculate $B - A$: $B - A = \begin{bmatrix} -2 & 5 \

Vedclass · Accepted Answer

None of these

Vedclass · Answer

(D) Given the equation $A + 2X = B$. Subtracting $A$ from both sides,we get $2X = B - A$. First,calculate $B - A$: $B - A = \begin{bmatrix} -2 & 5 \ 6 & 1 \end{bmatrix} - \begin{bmatrix} 3 & 4 \ 1 & -6 \end{bmatrix} = \begin{bmatrix} -2 - 3 & 5 - 4 \ 6 - 1 & 1 - (-6) \end{bmatrix} = \begin{bmatrix} -5 & 1 \ 5 & 7 \end{bmatrix}$. Now,$X = \frac{1}{2} (B - A) = \frac{1}{2} \begin{bmatrix} -5 & 1 \ 5 & 7 \end{bmatrix} = \begin{bmatrix} -2.5 & 0.5 \ 2.5 & 3.5 \end{bmatrix}$. Comparing this with the given options,the correct answer is none of these.

If $A = \begin{bmatrix} 3 & 4 \\ 1 & -6 \end{bmatrix}$ and $B = \begin{bmatrix} -2 & 5 \\ 6 & 1 \end{bmatrix}$,then find $X$ such that $A + 2X = B$.

Similar Questions

If $A = \begin{bmatrix} 2 & -3 \\ -4 & 1 \end{bmatrix}$,then $(A^T)^2 + (12 A)^T = $

$A$ and $B$ are two given matrices such that the order of $A$ is $3 \times 4$. If $A'B$ and $BA'$ are both defined,then:

If $m[-3, 4] + n[4, -3] = [10, -11]$,then $3m + 7n$ is equal to

If $A = \begin{bmatrix} 1 & 0 \\ -1 & 7 \end{bmatrix}$,$I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}$ and $A^{2} = 8A + kI$,then the value of $k$ is

If $A = \begin{bmatrix} 1 & 2 \\ 4 & 2 \end{bmatrix}$,then show that $|2A| = 4|A|$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module