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(B) Given that the order of $A$ is $3 	imes 4$,therefore the order of $A'$ is $4 	imes 3$.Since $A'B$ is defined,let the order of $B$ be $m 	imes n

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order of $B'A$ is $4 	imes 4$

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(B) Given that the order of $A$ is $3 	imes 4$,therefore the order of $A'$ is $4 	imes 3$.Since $A'B$ is defined,let the order of $B$ be $m 	imes n$. For $A'B$ to be defined,the number of columns in $A'$ must equal the number of rows in $B$. Thus,$m = 3$.Now,consider $BA'$. For $BA'$ to be defined,the number of columns in $B$ must equal the number of rows in $A'$. Since $A'$ is $4 	imes 3$,the number of rows is $4$. Thus,$n = 4$.Therefore,the order of $B$ is $3 	imes 4$.Consequently,the order of $B'$ is $4 	imes 3$.Finally,the order of $B'A$ is $(4 	imes 3) 	imes (3 	imes 4) = 4 	imes 4$.

$A$ and $B$ are two given matrices such that the order of $A$ is $3 \times 4$. If $A'B$ and $BA'$ are both defined,then:

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