If $p, q, r$ are simple propositions, then $(p \wedge q) \wedge (q \wedge r)$ is true then
$p, q, r$ are all false
$p, q, r$ are all true
$p, q$ are true and $r$ is false
$p$ is true and $q$ and $r$ are false
The statement $\sim(p\leftrightarrow \sim q)$ is :
Negation of the compound proposition : If the examination is difficult, then I shall pass if I study hard
If $\mathrm{p} \rightarrow(\mathrm{p} \wedge-\mathrm{q})$ is false, then the truth values of $p$ and $q$ are respectively
The contrapositive of the statement "If I reach the station in time, then I will catch the train" is
The following statement $\left( {p \to q} \right) \to $ $[(\sim p\rightarrow q) \rightarrow q ]$ is