If $P(A \cup B) = 0.8$ and $P(A \cap B) = 0.3,$ then $P(\bar A) + P(\bar B) = $

One card is drawn randomly from a pack of $52$ cards. The probability that it is a king or a spade is:

The odds in favour of getting a sum that is a multiple of $3$,when a pair of dice is thrown,is:

Let $A$ and $B$ be two independent events. The probability that both $A$ and $B$ occur together is $1/6$ and the probability that neither of them occurs is $1/3$. The probability of occurrence of $A$ is

For two events $A$ and $B$,the probability that at least one of them occurs is $0.6$ and the probability that both occur is $0.2$. Then $P(A) + P(B) = \dots$

If the odds in favour of an event be $3 : 5$,then the probability of non-occurrence of the event is