If int_{-1}^4 f(x) dx = 4 and int_2^4 {3 - f( | vedclass

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(D) Given that $\int_{-1}^4 f(x) dx = 4$ and $\int_2^4 \{3 - f(x)\} dx = 7$. First,solve the second integral: $\int_2^4 3 dx - \int_2^4 f(x) dx = 7$ $

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$5$

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(D) Given that $\int_{-1}^4 f(x) dx = 4$ and $\int_2^4 \{3 - f(x)\} dx = 7$. First,solve the second integral: $\int_2^4 3 dx - \int_2^4 f(x) dx = 7$ $[3x]_2^4 - \int_2^4 f(x) dx = 7$ $3(4 - 2) - \int_2^4 f(x) dx = 7$ $6 - \int_2^4 f(x) dx = 7$ $\int_2^4 f(x) dx = 6 - 7 = -1$. Now,use the property of definite integrals: $\int_{-1}^4 f(x) dx = \int_{-1}^2 f(x) dx + \int_2^4 f(x) dx$ $4 = \int_{-1}^2 f(x) dx + (-1)$ $\int_{-1}^2 f(x) dx = 4 + 1 = 5$.

If $\int_{-1}^4 f(x) dx = 4$ and $\int_2^4 \{3 - f(x)\} dx = 7$,then find the value of $\int_{-1}^2 f(x) dx$.

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