If $R$ is the set of all real numbers and $f: R \rightarrow R$ is defined by $f(x) = 3x^2 + 1$,then the set $f^{-1}([1, 6])$ is
- A$\{ -\sqrt{\frac{5}{3}}, 0, \sqrt{\frac{5}{3}} \}$
- B$[ -\sqrt{\frac{5}{3}}, \sqrt{\frac{5}{3}} ]$
- C$[ -\sqrt{\frac{1}{3}}, \sqrt{\frac{1}{3}} ]$
- D$( -\sqrt{\frac{5}{3}}, \sqrt{\frac{5}{3}} )$
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