If B and B^{prime} are the ends of the minor | vedclass

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(C) The given equation of the ellipse is $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$.Comparing this with $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$,we get $

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$24 	ext{ sq. unit}$

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(C) The given equation of the ellipse is $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$.Comparing this with $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$,we get $a^{2}=25$ and $b^{2}=9$,so $a=5$ and $b=3$.The ends of the minor axis are $B(0, 3)$ and $B^{\prime}(0, -3)$.The eccentricity $e$ is given by $e = \sqrt{1 - \frac{b^{2}}{a^{2}}} = \sqrt{1 - \frac{9}{25}} = \sqrt{\frac{16}{25}} = \frac{4}{5}$.The foci $S$ and $S^{\prime}$ are $(\pm ae, 0) = (\pm 5 	imes \frac{4}{5}, 0) = (\pm 4, 0)$.Thus,$S(4, 0)$ and $S^{\prime}(-4, 0)$.The rhombus $SBS^{\prime}B^{\prime}$ has diagonals $SS^{\prime}$ and $BB^{\prime}$.The length of diagonal $SS^{\prime} = 4 - (-4) = 8$.The length of diagonal $BB^{\prime} = 3 - (-3) = 6$.The area of a rhombus is $\frac{1}{2} 	imes 	ext{product of diagonals} = \frac{1}{2} 	imes 8 	imes 6 = 24 	ext{ sq. unit}$.

If $B$ and $B^{\prime}$ are the ends of the minor axis and $S$ and $S^{\prime}$ are the foci of the ellipse $\frac{x^{2}}{25}+\frac{y^{2}}{9}=1$,then the area of the rhombus $SBS^{\prime}B^{\prime}$ will be

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