If $f(x) = \frac{x - 3}{x + 1}$,then $f[f\{f(x)\}]$ equals

If $f(x) = \frac{\alpha x}{x + 1}$,$x \ne -1$,for what value of $\alpha$ is $f(f(x)) = x$?

$f: R - \left(-\frac{3}{5}\right) \rightarrow R$ is defined by $f(x) = \frac{3x-2}{5x+3}$,then $f \circ f(1)$ is

Let $f(x) = e^x$ and $g(x) = x^2$. Then,the number of solutions of $f(g(x)) = g(f(x))$ is equal to:

If $f$ is the greatest integer function and $g$ is the modulus function,then $(gof)\left( -\frac{5}{3} \right) - (fog)\left( -\frac{5}{3} \right) = $

If $f(x)$ and $g(x)$ are functions satisfying $f(g(x)) = x^3 + 3x^2 + 3x + 4$ and $f(x) = (\ln x)^3 + 3$,then the slope of the tangent to the curve $y = g(x)$ at $x = -1$ is: