If P=(0,1,2),Q=(4,-2,1),and O=(0,0,0),then an | vedclass

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(A) The direction ratios of the line segment $OQ$ are $(4-0, -2-0, 1-0)$,which are $(4, -2, 1)$.The direction ratios of the line segment $OP$ are $(0-

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$\frac{\pi}{2}$

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(A) The direction ratios of the line segment $OQ$ are $(4-0, -2-0, 1-0)$,which are $(4, -2, 1)$.The direction ratios of the line segment $OP$ are $(0-0, 1-0, 2-0)$,which are $(0, 1, 2)$.Let $	heta$ be the angle between $OP$ and $OQ$. The formula for the cosine of the angle between two vectors with direction ratios $(a_1, b_1, c_1)$ and $(a_2, b_2, c_2)$ is given by:$\cos 	heta = \frac{|a_1 a_2 + b_1 b_2 + c_1 c_2|}{\sqrt{a_1^2 + b_1^2 + c_1^2} \sqrt{a_2^2 + b_2^2 + c_2^2}}$Substituting the values:$\cos 	heta = \frac{|(4)(0) + (-2)(1) + (1)(2)|}{\sqrt{4^2 + (-2)^2 + 1^2} \sqrt{0^2 + 1^2 + 2^2}}$$\cos 	heta = \frac{|0 - 2 + 2|}{\sqrt{16 + 4 + 1} \sqrt{0 + 1 + 4}}$$\cos 	heta = \frac{0}{\sqrt{21} \sqrt{5}} = 0$Since $\cos 	heta = 0$,we have $	heta = \frac{\pi}{2}$.

If $P=(0,1,2)$,$Q=(4,-2,1)$,and $O=(0,0,0)$,then $\angle POQ$ is equal to

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