If y = cos(x^{circ}) and z = cos x,then frac{ | vedclass

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(C) Given $y = \cos(x^{\circ})$ and $z = \cos x$. Since $x^{\circ} = \frac{\pi x}{180}$ radians,we have $y = \cos\left(\frac{\pi x}{180}\right)$. Diff

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$\frac{\pi}{180} \sin(x^{\circ}) \operatorname{cosec} x$

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(C) Given $y = \cos(x^{\circ})$ and $z = \cos x$. Since $x^{\circ} = \frac{\pi x}{180}$ radians,we have $y = \cos\left(\frac{\pi x}{180}\right)$. Differentiating $y$ with respect to $x$: $\frac{dy}{dx} = -\sin\left(\frac{\pi x}{180}\right) \cdot \frac{\pi}{180} = -\frac{\pi}{180} \sin(x^{\circ})$. Differentiating $z$ with respect to $x$: $\frac{dz}{dx} = -\sin x$. Now,using the chain rule: $\frac{dy}{dz} = \frac{dy/dx}{dz/dx} = \frac{-\frac{\pi}{180} \sin(x^{\circ})}{-\sin x} = \frac{\pi}{180} \sin(x^{\circ}) \operatorname{cosec} x$.

If $y = \cos(x^{\circ})$ and $z = \cos x$,then $\frac{dy}{dz}$ is equal to

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