If f : mathbb{Z} rightarrow mathbb{Z} is defi | vedclass

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(B) Given,$f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3$. To find $f(11)$,substitute $x = 11$ into the expressio

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$8$

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(B) Given,$f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3$. To find $f(11)$,substitute $x = 11$ into the expression: $f(11) = 11^{9} - 11(11)^{8} - 2(11)^{7} + 22(11)^{6} + 11^{4} - 12(11)^{3} + 11(11)^{2} + 11 - 3$. Observe the terms: $11^{9} - 11(11)^{8} = 11^{9} - 11^{9} = 0$. $-2(11)^{7} + 22(11)^{6} = -2(11)^{7} + 2(11)(11)^{6} = -2(11)^{7} + 2(11)^{7} = 0$. $11^{4} - 12(11)^{3} + 11(11)^{2} = 11^{4} - 12(11)^{3} + 11^{3} = 11^{4} - 11(11)^{3} = 11^{4} - 11^{4} = 0$. Thus,the expression simplifies to: $f(11) = 0 + 0 + 0 + 11 - 3 = 8$.

If $f : \mathbb{Z} \rightarrow \mathbb{Z}$ is defined by $f(x) = x^{9} - 11 x^{8} - 2 x^{7} + 22 x^{6} + x^{4} - 12 x^{3} + 11 x^{2} + x - 3, \forall x \in \mathbb{Z}$,then $f(11) = $

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