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(D) Given $A = \begin{bmatrix} 1 & 0 & 2 \ 2 & 1 & 3 \ 3 & 2 & 4 \end{bmatrix}$.First,calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatrix} 1 & 0 & 2

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$\begin{bmatrix} 8 & 4 & 0 \ 3 & 8 & 4 \ 4 & 0 & 14 \end{bmatrix}$

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(D) Given $A = \begin{bmatrix} 1 & 0 & 2 \ 2 & 1 & 3 \ 3 & 2 & 4 \end{bmatrix}$.First,calculate $A^2 = A 	imes A$:$A^2 = \begin{bmatrix} 1 & 0 & 2 \ 2 & 1 & 3 \ 3 & 2 & 4 \end{bmatrix} \begin{bmatrix} 1 & 0 & 2 \ 2 & 1 & 3 \ 3 & 2 & 4 \end{bmatrix} = \begin{bmatrix} 1+0+6 & 0+0+4 & 2+0+8 \ 2+2+9 & 0+1+6 & 4+3+12 \ 3+4+12 & 0+2+8 & 6+6+16 \end{bmatrix} = \begin{bmatrix} 7 & 4 & 10 \ 13 & 7 & 19 \ 19 & 10 & 28 \end{bmatrix}$.Now,calculate $5A = 5 \begin{bmatrix} 1 & 0 & 2 \ 2 & 1 & 3 \ 3 & 2 & 4 \end{bmatrix} = \begin{bmatrix} 5 & 0 & 10 \ 10 & 5 & 15 \ 15 & 10 & 20 \end{bmatrix}$.And $6I = 6 \begin{bmatrix} 1 & 0 & 0 \ 0 & 1 & 0 \ 0 & 0 & 1 \end{bmatrix} = \begin{bmatrix} 6 & 0 & 0 \ 0 & 6 & 0 \ 0 & 0 & 6 \end{bmatrix}$.Finally,compute $A^2 - 5A + 6I$:$A^2 - 5A + 6I = \begin{bmatrix} 7 & 4 & 10 \ 13 & 7 & 19 \ 19 & 10 & 28 \end{bmatrix} - \begin{bmatrix} 5 & 0 & 10 \ 10 & 5 & 15 \ 15 & 10 & 20 \end{bmatrix} + \begin{bmatrix} 6 & 0 & 0 \ 0 & 6 & 0 \ 0 & 0 & 6 \end{bmatrix} = \begin{bmatrix} 7-5+6 & 4-0+0 & 10-10+0 \ 13-10+0 & 7-5+6 & 19-15+0 \ 19-15+0 & 10-10+0 & 28-20+6 \end{bmatrix} = \begin{bmatrix} 8 & 4 & 0 \ 3 & 8 & 4 \ 4 & 0 & 14 \end{bmatrix}$.

If $A = \begin{bmatrix} 1 & 0 & 2 \\ 2 & 1 & 3 \\ 3 & 2 & 4 \end{bmatrix}$,then $A^2 - 5A + 6I =$

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