If $A = \begin{bmatrix} 1 & 2 & 2 \\ 2 & 1 & 2 \\ 2 & 2 & 1 \end{bmatrix}$,then $A^3 - 4A^2 - 6A$ is equal to:

  • A
    $0$
  • B
    $A$
  • C
    $-A$
  • D
    $I$

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