यदि $3 \times { }^5 C_0 + 8 \times { }^5 C_1 + 13 \times { }^5 C_2 + 18 \times { }^5 C_3 + 23 \times { }^5 C_4 + 28 \times { }^5 C_5 = k \times 2^4$ है,तो $k=$

  • A
    $33$
  • B
    $37$
  • C
    $31$
  • D
    $30$

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Similar Questions

यदि ${C_0}, {C_1}, {C_2}, ......., {C_n}$ द्विपद गुणांक हैं,तो $2.{C_1} + {2^3}.{C_3} + {2^5}.{C_5} + ....$ का मान ज्ञात कीजिए।

कथन $-1$: $\sum_{r=0}^{n} (r+1) \binom{n}{r} = (n+2) 2^{n-1}$
कथन $-2$: $\sum_{r=0}^{n} (r+1) \binom{n}{r} x^r = (1+x)^n + nx(1+x)^{n-1}$

मान लीजिए $S_1 = \sum_{j=1}^{10} j(j-1) \binom{10}{j}$,$S_2 = \sum_{j=1}^{10} j \binom{10}{j}$,और $S_3 = \sum_{j=1}^{10} j^2 \binom{10}{j}$.
कथन $(A) : S_3 = 55 \times 2^9$
कारण $(R) : S_1 = 90 \times 2^8$ और $S_2 = 10 \times 2^8$

यदि $\binom{10}{2} + \binom{10}{3} + \binom{11}{4} + \binom{12}{5} + \binom{13}{6} = \binom{14}{r}$ है,तो $r = \dots$

यदि $C_0, C_1, C_2, \ldots, C_{10}$ द्विपद गुणांक $(1+x)^{10}$ के विस्तार में हैं,तो $C_0 C_6+C_1 C_7+C_2 C_8+C_3 C_9+C_4 C_{10}=$

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