જો $A$ ત્રીજા ચરણમાં હોય અને $\tan A = \frac{\sqrt{7}}{3}$ હોય,તો $18 - 16 \sin^2 \frac{A}{2} - 32 \sin \frac{A}{2} \sin \frac{5A}{2} = $

  • A
    -$6$
  • B
    $11$
  • C
    $5$
  • D
    $10$

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Similar Questions

$\sin ^4 \frac{\pi}{8}+\cos ^4 \frac{\pi}{8}+\sin ^4 \frac{3 \pi}{8}+\cos ^4 \frac{3 \pi}{8}+\sin ^4 \frac{5 \pi}{8}+\cos ^4 \frac{5 \pi}{8}+\sin ^4 \frac{7 \pi}{8}+\cos ^4 \frac{7 \pi}{8}=$

$\operatorname{cosec} 48^{\circ}+\operatorname{cosec} 96^{\circ}+\operatorname{cosec} 192^{\circ}+\operatorname{cosec} 384^{\circ}=$

જો $\sin \theta + \sin 2\theta + \sin 3\theta = \sin \alpha$ અને $\cos \theta + \cos 2\theta + \cos 3\theta = \cos \alpha$ હોય,તો $\theta$ ની કિંમત શોધો.

ધારો કે $|\cos \theta \cos (60^{\circ}-\theta) \cos (60^{\circ}+\theta)| \leq \frac{1}{8}$, જ્યાં $\theta \in [0, 2\pi]$. તો, તમામ $\theta \in [0, 2\pi]$ નો સરવાળો શોધો જ્યાં $\cos 3\theta$ તેની મહત્તમ કિંમત પ્રાપ્ત કરે છે: ($\pi$ માં)

$\frac{\sin 3A - \cos \left( \frac{\pi}{2} - A \right)}{\cos A + \cos (\pi + 3A)} = $

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