If $\cos A+\cos B+\cos C=0$ and $\sin A+\sin B+\sin C=0$,then $\cos (A-B)=$

  • A
    $0$
  • B
    $\frac{1}{2}$
  • C
    $-\frac{2}{3}$
  • D
    $-\frac{1}{2}$

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