If a, b, c neq 0 and belong to the set {1, 2, | vedclass

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(D) Given expression: $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ Simplify the denominator: $10^{-4} a+10^{-3} b+10^{

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$4$

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(D) Given expression: $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ Simplify the denominator: $10^{-4} a+10^{-3} b+10^{-2} c = \frac{a}{10^4} + \frac{b}{10^3} + \frac{c}{10^2} = \frac{a+10b+10^2c}{10^4}$ Substitute back into the logarithm: $\log _{10}\left(\frac{a+10 b+10^2 c}{\frac{a+10 b+10^2 c}{10^4}}\right) = \log _{10}(10^4)$ Using the property $\log_b(b^x) = x$: $\log _{10}(10^4) = 4$

If $a, b, c \neq 0$ and belong to the set $\{1, 2, 3, \ldots, 9\}$,then $\log _{10}\left(\frac{a+10 b+10^2 c}{10^{-4} a+10^{-3} b+10^{-2} c}\right)$ is equal to

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