If |x-2| leq 1,then | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the inequality $|x-2| \leq 1$. We know that the property $|x| \leq a$ is equivalent to $-a \leq x \leq a$. Applying this property to the giv

Vedclass · Accepted Answer

$x \in [1, 3]$

Vedclass · Answer

(A) Given the inequality $|x-2| \leq 1$. We know that the property $|x| \leq a$ is equivalent to $-a \leq x \leq a$. Applying this property to the given inequality,we get $-1 \leq x-2 \leq 1$. Adding $2$ to all parts of the inequality,we get $-1 + 2 \leq x \leq 1 + 2$. This simplifies to $1 \leq x \leq 3$. Therefore,the solution set is $x \in [1, 3]$.

If $|x-2| \leq 1$,then

Similar Questions

Solve the given inequality and show the graph of the solution on a number line:
$5x - 3 \geq 3x - 5$

If $|x+5| \geq 10$,then:

The set $\{x \in R: 16(2^x) > 16^{-1/x}\} = $

Solve the following inequality: $\left|\frac{3x-4}{2}\right| \leq \frac{5}{12}$

Solve for $x$ in the following inequality: $-5 \leq \frac{2-3x}{4} \leq 9$

Vedclass Test Series

Exam Paper Generator

Online Exam Module