If $\cot (\alpha + \beta ) = 0,$ then $\sin (\alpha + 2\beta ) = $
If $\cot (\alpha + \beta ) = 0,$ then $\sin (\alpha + 2\beta ) = $
- A
$\sin \alpha $
- B
$\cos \alpha $
- C
$\sin \beta $
- D
$\cos 2\beta $
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