If $\tan (\pi \cos \theta ) = \cot (\pi \sin \theta )$, then $\sin \left( {\theta + \frac{\pi }{4}} \right)$ equals
If $\tan (\pi \cos \theta ) = \cot (\pi \sin \theta )$, then $\sin \left( {\theta + \frac{\pi }{4}} \right)$ equals
- A
$\frac{1}{{\sqrt 2 }}$
- B
$\frac{1}{2}$
- C
$\frac{1}{{2\sqrt 2 }}$
- D
$\frac{{\sqrt 3 }}{2}$
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