If $\sin \theta = \sqrt 3 \cos \theta , - \pi < \theta < 0$, then $\theta = $
If $\sin \theta = \sqrt 3 \cos \theta , - \pi < \theta < 0$, then $\theta = $
- A
$ - \frac{{5\pi }}{6}$
- B
$ - \frac{{4\pi }}{6}$
- C
$\frac{{4\pi }}{6}$
- D
$\frac{{5\pi }}{6}$
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- [KVPY 2009]
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