If $A, B, C$ are three mutually exclusive and exhaustive events of an experiment such that $P(A)=2 P(B)=3 P(C)$,then $P(B)$ is equal to

  • A
    $\frac{1}{11}$
  • B
    $\frac{2}{11}$
  • C
    $\frac{3}{11}$
  • D
    $\frac{6}{11}$

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The probabilities of $A, B,$ and $C$ solving a problem are $\frac{1}{3}, \frac{2}{7},$ and $\frac{3}{8}$ respectively. If all three try to solve the problem simultaneously,the probability that exactly one of them will solve it is:

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